Создание модуля расширения для Python на языке Си

#include <Python.h>
 
PyObject *hello( PyObject *self, PyObject *args, PyObject *kwargs )
{
    char *who = 0;
    static char *keywords[] = {"who", NULL};
    PyObject *result = 0;
 
    if (!PyArg_ParseTupleAndKeywords(args, kwargs, "s", keywords, &who))
    {
        return NULL;
    }
 
    result = PyString_FromString("Hello ");
    PyString_Concat(&result, PyString_FromString(who));
    return result;
}
 
 
static PyMethodDef example_methods[] = 
{
    { "hello", (PyCFunction) hello, METH_KEYWORDS, "hello(who) -- return \"Hello who\"" },
    { NULL, 0, 0, NULL }
};
 
 
PyMODINIT_FUNC initexample()
{
    (void) Py_InitModule("example", example_methods);
 
    if (PyErr_Occurred())
    {
        PyErr_SetString(PyExc_ImportError, "example module init failed");
    }
}

#include <Python.h>
 
PyObject *hello( PyObject *self, PyObject *args, PyObject *kwargs )
{
    char *who = 0;
    static char *keywords[] = {"who", NULL};
 
    if (PyArg_ParseTupleAndKeywords(args, kwargs, "s", keywords, &who))
    {
        return PyUnicode_FromFormat("Hello %s", who);
    }
    return NULL;
}
 
 
static PyMethodDef example_methods[] = 
{
    { "hello", (PyCFunction) hello, METH_KEYWORDS, "hello(who) -- return \"Hello who\"" },
    { NULL, 0, 0, NULL }
};
 
 
static struct PyModuleDef example_module = 
{
    PyModuleDef_HEAD_INIT,
    "example",
    NULL,
    -1,
    example_methods
};
 
 
PyMODINIT_FUNC PyInit_example(void)
{
    return PyModule_Create(&example_module);
}

from distutils.core import setup
from distutils.extension import Extension
examplemodule = Extension(name="example", sources=['example.c', ])
setup(name="example", ext_modules=[examplemodule])